Question
Construct a trapezium $\text{ABCD}$ in which $\ce{AB\|DC}, \angle\text{A}=105^\circ,AD = 3\ cm, AB = 4\ cm$ and $CD = 8\ cm$.
✓
Answer
$\angle\text{A}+\angle\text{D}=180^\circ$ $+150^\circ\angle\text{D}=180^\circ$ $\angle\text{D}=75^\circ$ 
Steps of Construction:
$1.$ Draw $\text{AB} = 4\ cm$
$2.$ Draw $\overline{\text{AX}}$ such that $\angle\text{BAX}=105^\circ$
$3.$ Mark a point $D$ on $\text{AX}$ such that $\text{AD} = 3\ cm$
$4.$ Draw $\overline{\text{DY}}$ such that $\angle\text{ADY}=75^\circ$
$5.$ Mark a point $C$ such that $\text{CD} = 8\ cm$
$6.$ Join $\text{BC}$.
Hence, $\text{ABCD}$ is the required trapezium.
Steps of Construction:
$1.$ Draw $\text{AB} = 4\ cm$
$2.$ Draw $\overline{\text{AX}}$ such that $\angle\text{BAX}=105^\circ$
$3.$ Mark a point $D$ on $\text{AX}$ such that $\text{AD} = 3\ cm$
$4.$ Draw $\overline{\text{DY}}$ such that $\angle\text{ADY}=75^\circ$
$5.$ Mark a point $C$ such that $\text{CD} = 8\ cm$
$6.$ Join $\text{BC}$.
Hence, $\text{ABCD}$ is the required trapezium.
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