Question
Construct a triangle with sides $5cm, 6cm$ and $7cm$ and then another triangle whose sides are $\frac{7}{5}$ of the corresponding sides of the first triangle.
✓
Answer
Steps of construction:
- Draw a line segment $BC = 5cm.$
- With centre B and radius 6cm and with centre C and radius 7cm, draw arcs intersecting each other at A.
- Join AB and AC. Then ABC is the triangle.
- Draw a ray BX making an acute angle with BC and cut off 7 equal parts making $BB_1 = B_1B_2 = B_2B_3 = B_3B_4 = B_4B_5 = B_5B_6 = B_6B_7.$
- Join B_5 and C.
- From $B_7,$ draw $B_7C’$ parallel to $B_5C$ and $C’A’$ parallel $CA$. Then $\triangle\text{A}’\text{BC}'$ is the required triangle.
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