Question
Construct a triangle XYZ in which $\angle\text{Y}=30^\circ,$ $\angle\text{Z}=90^\circ$ and XY + YZ + ZX = 11cm.
✓
Answer
Steps of construction:
- Draw a line segment AB of 11cm.
- Draw $\angle\text{DAB}=30^\circ$ and $\angle\text{FBA}=90^\circ.$
- Draw the angle bisectors of $\angle\text{DAB}$ and $\angle\text{EBA}$ which intersect each other at A.
- Draw the perpendicular bisector of XA and XB which intersect AB at Y and Z respectively
- Join XY and XZ.
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