Question
Construct a $\triangle\text{ABC}$ in which $BC = 3.4\ cm, AB - AC = 1.5\ cm$ and $\angle\text{B}=45^\circ.$
✓
Answer
Steps of Construction:
$1.$ Construct a line segment $BC$ of $3.4\ cm$.
$2.$ At the point $B$, draw $\angle\text{XBC}=45^\circ$
$3.$ Keeping $B$ as centre and radius $1.5\ cm$ draw an arc which intersects $XB$ at $D$.
$4.$ Join $DC$.
$5.$ Draw the perpendicular bisector of $DC$ which intersects $DB$ at $A$.
$6.$ Join $AC$.
Hence $\triangle\text{ABC}$ is the required triangle.
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