Question
Construct a $\triangle\text{ABC}$ in which $BC = 3.6\ cm, AB + AC = 4.8\ cm$ and $\angle\text{B}=60^\circ. $
✓
Answer
Steps of Construction:
$1.$ Construct a line segment $BC$ of $3.6\ cm$.
$2.$ At the point $B$, draw $\angle\text{XBC}=60^\circ.$
$3.$ Keeping $B$ as center and radius $4.8\ cm$ draw an arc which intersects $XB$ at $D$.
$4.$ Join $DC$.
$5.$ Draw the perpendicular bisector of $DC$ which intersects $DB$ at $A$.
$6.$ Join $AC$.
Hence $\triangle\text{ABC}$ is the required triangle.
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