Question
Construct a $\triangle\text{ABC}$ in which $BC = 5.8\ cm$,$\angle\text{B}=\angle\text{C}=30^\circ.$ Measure $AB$ and $AC$. What do you observe?
✓
Answer
Steps for construction:
Step I: Draw $BC = 5.8cm$
Step II: Draw $\angle\text{BCY}=30^\circ$
Step III: Draw $\angle\text{CBX}=30^\circ$
Step IV: The ray $BX$ an $CY$ intersect at $A$. Then, $ABC$ is the required triangle. On measuring $AB$ and $AC: AB = AC = 3.4cm.$
Step I: Draw $BC = 5.8cm$
Step II: Draw $\angle\text{BCY}=30^\circ$
Step III: Draw $\angle\text{CBX}=30^\circ$
Step IV: The ray $BX$ an $CY$ intersect at $A$. Then, $ABC$ is the required triangle. On measuring $AB$ and $AC: AB = AC = 3.4cm.$
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