Question
Construct a $\triangle\text{ABC}$ in which $BC = 7\ cm$,$\angle\text{A}=45^\circ.$and $\angle\text{C}=75^\circ.$

Answer

By angle sum property:$\angle\text{B}=180^\circ-\angle\text{A}-\angle\text{C}$
$=180^\circ-45^\circ-75^\circ$
$=60^\circ$
Steps for construction:
Step I: Draw $AB = 7\ cm$
Step II: Draw $\angle\text{BAX}=45^\circ$
Step III: Draw $\angle\text{ABY}=60^\circ$
Step IV: The ray $AX$ an $BY$ intersect at $C$.
Then, $ABC$ is the required triangle.

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