Question
Construct an equilateral triangle ABC such that it's one side = 5.5 cm. Construct a circumcircle to this triangle.
✓
Answer
Steps of Construction :
(i) Draw a line segment $A B=5.5 cm$
(ii) With centres $A$ and $B$ and radius $5.5 cm$, draw two arcs intersecting each other at $C$.
(iii) Join $A C$ and $B C$.
$\triangle A B C$ is the required triangle.
(iv) Draw perpendicular bisectors of sides $A C$ and $B C$ which intersect each other at $O$.
(v) Join $O A, O B$ and $O C$.
(vi) With centre $O$ and radius $OA$ or $OB$ or $OC$, draw a circle which passes through $A, B$ and $C$. This is the required circumcircle.
(i) Draw a line segment $A B=5.5 cm$
(ii) With centres $A$ and $B$ and radius $5.5 cm$, draw two arcs intersecting each other at $C$.
(iii) Join $A C$ and $B C$.
$\triangle A B C$ is the required triangle.
(iv) Draw perpendicular bisectors of sides $A C$ and $B C$ which intersect each other at $O$.
(v) Join $O A, O B$ and $O C$.
(vi) With centre $O$ and radius $OA$ or $OB$ or $OC$, draw a circle which passes through $A, B$ and $C$. This is the required circumcircle.
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