Question
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
✓
Answer
Steps of Construction :
(i) Draw a line segment $MN =5.8 cm$.
(ii) At $M$ and $N$, draw two rays making an angle of $30^{\circ}$ each which intersect each other at $P$.
(iii) Now draw the angle bisectors of $\angle M$ and $\angle N$ which intersects each other at I.
(iv) From I, draw the perpendicular IL on MN.
(v) With centre I and radius IL, draw a circle which touches the sides of the $\triangle$ PMN internally.
On measuring the required incircle and its radius is $0.6 cm$.
(i) Draw a line segment $MN =5.8 cm$.
(ii) At $M$ and $N$, draw two rays making an angle of $30^{\circ}$ each which intersect each other at $P$.
(iii) Now draw the angle bisectors of $\angle M$ and $\angle N$ which intersects each other at I.
(iv) From I, draw the perpendicular IL on MN.
(v) With centre I and radius IL, draw a circle which touches the sides of the $\triangle$ PMN internally.
On measuring the required incircle and its radius is $0.6 cm$.
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