Question
Construct an isosceles triangle in which: $PQ = QR, PR = 4.5 \ cm$ and $\angle R = 60^\circ $
✓
Answer
In $\triangle PQR,$
$PQ = QR ....($given$)$
$\Rightarrow \angle PRQ = \angle RPQ = 60^\circ $
Steps:
$1$. Draw $PR = 4.5\ cm.$
$2$. Construct $\angle PRU = 60^\circ $ and $\angle RPV = 60$
$3.$ Ray $RU$ and $PV$ meet at $Q$.
Thus, $\text{PQR}$ is the required triangle.
$PQ = QR ....($given$)$
$\Rightarrow \angle PRQ = \angle RPQ = 60^\circ $
Steps:
$1$. Draw $PR = 4.5\ cm.$
$2$. Construct $\angle PRU = 60^\circ $ and $\angle RPV = 60$
$3.$ Ray $RU$ and $PV$ meet at $Q$.
Thus, $\text{PQR}$ is the required triangle.
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