Question
Construct an isosceles triangle in which: $XY = XZ, YZ = 5.5 \ cm$ and $\angle X = 60^\circ $

Answer

In $\triangle XYZ,$
$XY = XZ ....($given$)$
$c \angle XZY = \angle XYZ ....(i)$
$\angle X = 60^\circ ....($given$)$
Now, $\angle X + \angle Y + \angle Z = 180^\circ $
$60^\circ + \angle Y + \angle Y = 180^\circ ....[$From $(i)]$
$2\angle Y = 120^\circ $
$\Rightarrow \angle Y = 60^\circ = \angle Z$
Steps:
$1.$ Draw $YZ = 5.5\ cm.$
$2.$ Construct $\angle YZP = 60^\circ $ and $\angle ZYQ = 60^\circ $
$3.$ Ray $ZP$ and $YQ$ meet at $x.$
Thus, $\text{XYZ}$ is the required triangle.

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