Question
Construct the composition table for ×4 on set S = {0, 1, 2, 3}.

Answer

Here,
41 = Remainder obtained by dividing 1 × 1 by 4 = 1
41 = Remainder obtained by dividing 0 × 1 by 4 = 0
43 = Remainder obtained by dividing 2 × 3 by 4 = 2
43 = Remainder obtained by dividing 3 × 3 by 4 = 1
Therefore,
The composition table is as follows:
x4 0 1 2 3
0 0 0 0 0
1 0 1 2 3
2 0 2 0 2
3 0 3 2 1

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