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Binary Operations — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsBinary Operations3 Marks
Question
Construct the composition table for ×5 on Z5 = {0, 1, 2, 3, 4}.
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Answer

Here,
1×51 = Remainder obtained by dividing 1 × 1 by 5 = 1
3×54 = Remainder obtained by dividing 3 × 4 by 5 = 2
4×54 = Remainder obtained by dividing 4 × 4 by 5 = 1
Therefore,
The composition table is as follows:
×5 0 1 2 3 4
0 0 0 0 0 0
1 0 1 2 3 4
2 0 2 4 1 3
3 0 3 1 4 2
4 0 4 3 2 1

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