Question
Construct the switching circuit for the statement $(p \wedge q) \vee(\sim p) \vee(p \wedge \sim q)$
✓
Answer
Let
$p =$ Switch $S_1$ is closed
$q =$ Switch $S_2$ is closed
$\sim p=$ switch $\quad S_1^{\prime}$ and $\sim q \equiv S_2^{\prime}$
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