Question
Consult the table of standard electrode potentials and suggest three substances that can oxidise ferrous ions under suitable conditions.
✓
Answer
Oxidation of ferrous ion means :
$Fe^{2+ \rightarrow } Fe^{3+} + e^- ; E^0_{Fe3+/Fe2+} = 0.77V$
Any substance which standard electrode potential is more than that of $Fe^{+3 }/F^{+2}$ can oxidise ferrous ions.
$($refer to the table given in book$)$
The $EMF$ of the substance whose reduction potentials greater than $0.77V$ will oxidised ferrous ion.
For example $Br_{2 },Cl_{2},$ and $F_2.$
$Fe^{2+ \rightarrow } Fe^{3+} + e^- ; E^0_{Fe3+/Fe2+} = 0.77V$
Any substance which standard electrode potential is more than that of $Fe^{+3 }/F^{+2}$ can oxidise ferrous ions.
$($refer to the table given in book$)$
The $EMF$ of the substance whose reduction potentials greater than $0.77V$ will oxidised ferrous ion.
For example $Br_{2 },Cl_{2},$ and $F_2.$
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Column $II$
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$(e)$ |
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$(f)$ |
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$(g)$ |
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