MCQ
Conventional flow of current will always be from:
- ✓$p$ type $\rightarrow n$ type
- B$n$ type $\rightarrow p$ type
- C$n$ Type $\rightarrow n$ type
- DNone of these
✓
Answer
Correct option: A.
$p$ type $\rightarrow n$ type
The holes in the covalent bonds of $p-$type semiconductor. They appear to move towards $n-$type semiconductor. Because the electrons in the covalent bonds of $n-$type semiconductor $($not free electrons$)$ jump towards $p-$type semiconductor due to plenty of holes available in the covalent bonds at $p-$side.
Hence, conventional current flow from $p-$type to $n-$type.
Hence, conventional current flow from $p-$type to $n-$type.
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