For $Cu$, ${\text{m}} = \frac{{{\text{E}} \times {\text{Q}}}}{{{\text{nF}}}} = $ $\frac{{63.5}}{{2 \times {\text{F}}}} \times 0.2\,{\text{F}} = 6.36\,{\text{g}}$
Hence; $(1)$ is correct.
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Statement $I:$ For $KI$, molar conductivity increases steeply with dilution.
Statement $II:$ For carbonic acid, molar conductivity increases slowly with dilution. In the light of the above statements, choose the correct answer from the options given below:
(Given : $R =0.083\, L\, bar \,K ^{-1} \,mol ^{-1}$ )
$ + \frac{1}{2}\frac{{d\left[ C \right]}}{{dt}} = - \frac{1}{3}\frac{{d\left[ D \right]}}{{dt}} = + \frac{1}{4}\frac{{d\left[ A \right]}}{{dt}} = \frac{{ - d\left[ B \right]}}{{dt}}$
the reaction is