MCQ
Correct order for reaction with alcoholic $KOH$
  • $a > c > b > d $
  • B
    $a > b > c > d$
  • C
    $d > b > c > a$
  • D
    $a > d > b > c$

Answer

Correct option: A.
$a > c > b > d $
a
This is an example of elimination reaction. Alcoholic $KOH$ shows $E 2$ elimination reaction. The reactivity order for $E 2$ elimination reaction depends upon the stability of the product formed as shown below :

$3^{\circ}>2^{\circ}>1^{\circ}$

The order of leaving group in $E 2$ elimination reaction is shown below :

$R - I > R - Br > R - Cl$

Therefore, the correct order for reaction with alcoholic $KOH$ is as follows :

$a >  c > b > d$

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