MCQ
The bond angle of water is ${104.5^o}$ due to
  • Repulsion between lone pair and bond pair
  • B
    $s{p^3}$ hybridization of $O$
  • C
    Bonding of ${H_2}O$
  • D
    Higher electronegativity of $O$

Answer

Correct option: A.
Repulsion between lone pair and bond pair
a
The bond angle in $H _2 O$ is $104.5^{\circ}$ due to the presence of two lone pair of electrons. This fact can be explained with the help of valence shell electron pair repulsion theory ($VSEPR$).

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