MCQ
Correct order of acidic strength
- A$HF > HCl > HBr > HI$
- ✓$H_3PO_2 > H_3PO_3 > H_3PO_4$
- C$B(OH)_3 > H_2CO_3 > HNO_3$
- D$H_2O > H_2S > H_2Se > H_2Te$
$O _3$ can acts as only oxidizing agent due to its unstable nature and decomposes to give nascent oxygen.
$HNO _3$ : Nitrogen is present in its highest oxidation state i.e., $+5$ so it can act as only oxidizing agent.
$SO _2$ :Sulphur is present in $+4$ oxidation state so it can act as both oxidizing as well as reducing agent.
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$Cu^+ /Cu = + 0.52\, V$,
$Fe^{3+} /Fe^{2+} = +0.7 7\, V$,
$\frac{1}{2}{I_2}\left( s \right)/{I^ - }\, = + 0.54\,V,$
$Ag^+ /Ag = + 0.88\,V$.
Based on the above potentials, strongest oxidizing agent will be
Reason $(R)$ : Oxygen forms $\mathrm{p} \pi-\mathrm{p} \pi$ multiple bonds with itself and other elements having small size and high electronegativity like $\mathrm{C}, \mathrm{N}$, which is not possible for sulphur.
In the light of the above statements, choose the most appropriate answer from the options given below :
(Given atomic member $\mathrm{V}=23, \mathrm{Mn}=25, \mathrm{Cr}=24$ )