MCQ
Electrode potentials $(E^o)$ are given below

$Cu^+ /Cu = + 0.52\, V$,

$Fe^{3+} /Fe^{2+} = +0.7 7\, V$,

$\frac{1}{2}{I_2}\left( s \right)/{I^ - }\, =  + 0.54\,V,$

$Ag^+ /Ag = + 0.88\,V$.

Based on the above potentials, strongest oxidizing agent will be

  • A
    $Cu^+$
  • B
    $Fe^{3+}$
  • $Ag^+$
  • D
    $I_2$

Answer

Correct option: C.
$Ag^+$
c
Higher the value of reduction potential stronger will be the oxidising hence based on the given values $Ag^+$ will be strongest oxidizing agent

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