- ✓$CO_3^{2 - } > C{O_2} > CO$
- B$C{O_2} > CO > CO_3^{2 - }$
- C$CO > C{O_2} > CO_3^{2 - }$
- DNone of these
i.e. $:\mathop C\limits^ - \equiv \mathop O\limits^ + :$ is $3,$ that of $O = C = O$ is $2$
while that of $CO_3^{2 - }$ ion is $1.33.$
Since the bond length increases as the bond order decreases, i.e. $CO < C{O_2} < CO_3^{2 - }$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$I.$ $1$ molecule of oxygen
$II.$ $1$ atom of nitrogen
$III.$ $1 \times {10^{ - 10}}$ $g$ molecular weight of oxygen
$IV.$ $1 \times {10^{ - 10}}$ $g$ atomic weight of copper
$\left[\right.$ Given : $pK _{ b }\left( NH _3\right)=4.745$
$\log 2=0.301$
$\log 3=0.477$
$T =298\,K ]$
$2{H_2}{O_2}(l) \rightleftharpoons {H_2}O(l) + {O_2}(g)$
$(R = 83\, JK^{-1}\, mol^{-1})$
$Image$
is/are
$MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$,
here $10\, ml$ of $0.1\, M$ $KMn{O_4}$ is equivalent to