MCQ
Correct set of four quantum numbers for valence electron of rubidium $ (Z = 37)$ is
- ✓$5,\,0,\,0,\, + \frac{1}{2}$
- B$5,\,1,\,0,\, + \frac{1}{2}$
- C$5,\,1,\,1,\, + \frac{1}{2}$
- D$6,\,0,\,0,\, + \,\frac{1}{2}$
$1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^{10}}\,4{s^2}\,4{p^6}\,5{s^1}$
So for the valence shell electron $(5{s^1})$
$n = 5,\,l = 0,\,m = 0,\,s = + \frac{1}{2}$
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