MCQ
$\cos 45^{\circ}=?$
- A$\sin 45^{\circ}$
- B$\sec 45^{\circ}$
- C$\cot 45^{\circ}$
- D$\tan 45^{\circ}$
✓
Answer
$\sin 45^{\circ}$
$\cos 45^{\circ}=\frac{1}{\sqrt{2}}, \sin 45^{\circ}=\frac{1}{\sqrt{2}}$
$\therefore \cos 45^{\circ}=\sin 45^{\circ}$
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