MCQ
$(\cos \alpha+\cos \beta)^2+(\sin \alpha+\sin \beta)^2=$
  • $4 \cos ^2\left(\frac{\alpha-\beta}{2}\right)$
  • B
    $4 \sin ^2\left(\frac{\alpha-\beta}{2}\right)$
  • C
    $4 \cos ^2\left(\frac{\alpha+\beta}{2}\right)$
  • D
    $4 \sin ^2\left(\frac{\alpha+\beta}{2}\right)$

Answer

Correct option: A.
$4 \cos ^2\left(\frac{\alpha-\beta}{2}\right)$
(A)
$(\cos \alpha+\cos \beta)^2+(\sin \alpha+\sin \beta)^2$
$\begin{array}{l}=\cos ^2 \alpha+\cos ^2 \beta+2 \cos \alpha \cos \beta+\sin ^2 \alpha \\ +\sin ^2 \beta+2 \sin \alpha \sin \beta\end{array}$
$=2\{1+\cos (\alpha-\beta)\}=4 \cos ^2\left(\frac{\alpha-\beta}{2}\right)$

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