MCQ
$\cot (45^\circ + \theta )\cot (45^\circ - \theta ) = $
- A$-1$
- B$0$
- ✓$1$
- D$\infty $
$= \tan (90^\circ - 45^\circ - \theta )\cot (45^\circ - \theta )$
$ = \tan (45^\circ - \theta )\cot (45^\circ - \theta ) = 1$.
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