cot 5^o -tan5^o -2 tan10^o -4 tan 20^o -8 cot40^o is equal to - Vidyadip

MCQ

$cot 5^o$ -$tan5^o$ -$2$ $tan10^o$ -$4$ $tan 20^o$ -$8$ $cot40^o$ is equal to

✓
$0$
B
$4\tan {40^o}$
C
$8\tan {40^o}$
D
$8\cot {40^o}$

✓

Answer

Correct option: A.

$0$

a
Use the relation $\cot \theta - \tan \theta = 2\cot 2\theta$

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