MCQ
${C_{{\rm({daimond})}}}$ $+$ ${O_2} \to C{O_2};$ $\Delta H = - 395.3\,kJ/mole$

${C_({graphite)}} + {O_2} \to C{O_2};\,\Delta H = - 393.4\,kJ/mole$

${C_({graphite})} \to {C_{{\rm({diamond})}}};\,\Delta H = $

  • A
    $-3.8$
  • B
    $-1.9$
  • C
    $3.8$
  • $1.9$

Answer

Correct option: D.
$1.9$
(d) By $(ii) -(i)$, ${C_({graphite})} \to {C_({diamond})}\,,\,\,\Delta H = + 1.9$.

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