MCQ
$Cu^{2+} + 2e^-\to Cu$. On increasing $[Cu^{2+}]$ concentration, electrode potential
- ✓Increases
- BDecreases
- CWill remain unchanged
- DFirst increases, then decreases
✓
Answer
Correct option: A.
Increases
a
$\mathrm{Cu}_{(\mathrm{aq})}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}(\mathrm{s})$
$\mathrm{Cu}_{(\mathrm{aq})}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}(\mathrm{s})$
$\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}=\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{0}-\frac{0.06}{2} \log \left|\frac{1}{\mathrm{Cu}^{2+}}\right|$
$=\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{0}+\frac{0.06}{2} \log \left|\mathrm{Cu}^{2+}\right|$
$\left|\mathrm{Cu}^{2+}\right|$ increases, $\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}$ also increases
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