MCQ
${d \over {dx}}{\log _7}({\log _7}x)=$
- A${1 \over {x{{\log }_e}x}}$
- B${{{{\log }_e}7} \over {x{{\log }_e}x}}$
- ✓${{{{\log }_7}e} \over {x{{\log }_e}x}}$
- D${{{{\log }_7}e} \over {x{{\log }_7}x}}$
${1 \over {x{{\log }_e}x}} \cdot \frac{1}{{{\log }_{e}}7}$ = $\frac{{{\log }_{7}}e}{x{{\log }_{ex}}}$
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