MCQ
${d \over {dx}}\log |x|{\rm{ }} = ......,(x \ne 0)$
- ✓${1 \over x}$
- B$ - {1 \over x}$
- C$x$
- D$ - x$
Hence $\frac{d}{{dx}}\left\{ {\log |x|} \right\} = \frac{1}{x}$, if $x > 0$
$ = \left( {\frac{1}{{ - x}}} \right)( - 1) = \frac{1}{x}$, if $x < 0$
Thus $\frac{d}{{dx}}\left\{ {\log |x|} \right\} = \frac{1}{x}$, if $x \ne 0$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.