MCQ
${{{d^2}x} \over {d{y^2}}}$= . . .
- A${1 \over {{{(dy/dx)}^2}}}$
- B${{\left( {{d^2}y/d{x^2}} \right)} \over {{{\left( {dy/dx} \right)}^2}}}$
- C${{{d^2}y} \over {d{x^2}}}$
- ✓${{\left( { - {d^2}y/d{x^2}} \right)} \over {{{\left( {dy/dx} \right)}^2}}}$