MCQ
$\frac{{{d^2}y}}{{d{x^2}}} = x{e^x} + 1$ નું ઉકેલ $............$
- A$y = \left( {x - 1} \right){e^x} + \frac{1}{2}{x^2} + {C_1}x + {C_2}$
- ✓$y = \left( {x - 2} \right){e^x} + \frac{1}{2}{x^2} + {C_1}x + {C_2}$
- C$y = \left( {x + 2} \right){e^x} + \frac{1}{2}{x^2} + {C_1}x + {C_2}$
- Dએક પણ નહીં.