MCQ
Decay of $_{92}{U^{235}}$is .....order reaction
- A$0$
- ✓$1$
- C$2$
- D$3$
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Reason : $SO_2$ is a reducing agent
[Atomic masses (in $u$) $Mn =55 ; Cl =35.5 ; O =16, I =127, Na =23, K =39, S =32]$
$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.