MCQ
Decimal expansion of $\frac{23}{\left(2^3 5^2\right)}$ will be:
  • Terminating
  • B
    Non-terminating
  • C
    Non terminating and repeating.
  • D
    Non-terminating and non-repeating

Answer

Correct option: A.
Terminating
(a)
We know by a theorem that, If $x=\frac{p}{q}$ be a rational number, such that the prime factorization of $q$ is in the form $2^n 5^m$, where $n, m$ are non-negative integers. Then $x$ has a decimal expansion which terminates.
Hence, Decimal expansion of $\frac{23}{2^3 5^2}$ will be terminating
So, the correct option is (a).

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