$\phi_E=\overrightarrow{E}.\overrightarrow{A}={EA}\cos\theta$
Its S.I unit is $(Nm^{2}C^{-1})$ The Gaussian surface is cylindrical and field is radial. At the cylindrical part of the surface, cylindrical part of the surface, $ \overrightarrow{E}$ is normal to the surface at every point and its magnitude is constant (since it depends only on r). By Gauss’s theorem : $ \oint \overrightarrow{E}.{d}\overrightarrow{S}=\frac{q}{\in_0}$$\therefore(2\pi{rl})=\frac{\lambda{l}}{\in_0}$
$\text{or}\text{ }\text{ } E=\frac{\lambda}{2\pi\in_0r}$
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