MCQ
$\Delta U^o$ of combustion of $CH_{4(g)}$ at certain temperature is $-393\,kJ/mol$ . Then value of $\Delta H^o$ is
- AZero
- ✓$<\, \Delta U^o$
- C$>\Delta U^o$
- Dequal to $\Delta U^o$
$CH _{4( g )}+2 O _{2( g )} \rightarrow CO _{2( g )}+2 H _2 O _{( l )}$
Here, $\Delta n _{ g }=1-3=-2$
$\Delta H ^0=\Delta U ^0+\Delta n _{ g } RT$
$\Delta H ^0=-393-2 RT$
$\therefore \Delta H ^0\,<\,\Delta U ^0$
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