Maharashtra Boardमराठी माध्यमSTD 10Maths - मराठीQuestion Bank2 Marks
Question
∆ABP ~ ∆DEF आणि A(∆ABP) : A(∆DEF) = 144:81 तर AB:DE = ?
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Answer
$\frac{A(\triangle ABP )}{ A (\triangle DEF )}=\frac{144}{81}$....(i) [पक्ष] $\frac{A(\triangle A B P)}{A(\triangle D E F)}=\frac{A B^2}{D E^2}$.......(ii) [समरूप त्रिकोणांच्या क्षेत्रफळांचे प्रमेय] $\therefore \frac{A B^2}{D E^2}=\frac{144}{81}$..........[(i) आणि (ii) वरून] $\therefore \frac{ AB }{ DE }=\frac{12}{9}$ किंवा $\frac{4}{3}$ .......[दोन्ही बाजूंचे वर्गमूळ घेऊन]
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