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Continuity and Differentiability — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsContinuity and Differentiability1 Mark
MCQ
Derivative of $\cos ^{-1}\left(4 x^3-3 x\right)$ :
  • A
    $\frac{3}{\sqrt{1-x^2}}$
  • ✓
    $\frac{-3}{\sqrt{1-x^2}}$
  • C
    $\frac{1}{\sqrt{1+x^2}}$
  • D
    $-\frac{3}{\sqrt{1+x^2}}$
✓

Answer

Correct option: B.
$\frac{-3}{\sqrt{1-x^2}}$
Put $x=\cos \theta$
$\cos ^{-1}\left(4 x^3-3 x\right)=\cos ^{-1}\left(4 \cos ^3 \theta-3 \cos \theta\right)$
$\Rightarrow \cos ^{-1}(\cos 3 \theta)=3 \theta=3 \cos ^{-1} x[\because x=\cos \theta]$
$\therefore \frac{d}{d x}\left(3 \cos ^{-1} x\right)=3 \frac{d}{d x}\left(\cos ^{-1} x\right)=3\left\{\frac{-1}{\sqrt{1-x^2}}\right\}$
$=\frac{-3}{\sqrt{1-x^2}}$
Hence correct option is $(B).$

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