Question
Derive the expression for the heat produced due to a current 'l' flowing for a time interval 't' through a resistor 'R' having a potential difference 'V' across its ends. With which name is the
relation known? How much heat will an instrument of 12W produce in one minute if it is connected to a battery of 12V?
Study the following electric circuit and find.
  1. The current flowing in the circuit and
  2. The potential difference across $10\Omega$ resistor.

Answer

we know that $E =\frac{ P }{ t }$
also $P = VI$
substituting we get
$E = VIt$
but $V =\mid R$
substituting we get
$E =| RIt =| * Rt$ T
his is the relation and its called joules law of heating
$P=12 W$
$t =60 sec$
$V =12 V$
$P= VI I$
$=\frac{ p }{ v }=\frac{12}{12}$
$=1 A$
now
$H = VIt =12(1) 60$
$=12(60)=720 $
$J= R _1= R _1+ R _2=10+2030 \Omega $
$V=3 V 1$.
From ohm's law $V = IR$.
$3=1 \times 30 \Rightarrow 1=\frac{3}{30}=\frac{1}{10}$ Ampere or 0.1 A
2. Potential difference across $10 \Omega$ reistor.
$V = I R$
$=\frac{1 \times 10}{10}=1$ volt.

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