Question
Determine if the $32, 48, 70, 210$ are in proportion.
✓
Answer
$32 : 48$ $=\frac{32}{48}=\frac{32 \div 16}{48 \div 16}$[$\therefore$$H.C.F.(32, 48) = 16]$
$=\frac{2}{3}$ $= 2 : 3$
$70 : 210$ $=\frac{70}{210}=\frac{70 \div 70}{210 \div 70}$[$\therefore$$H.C.F. (70, 210) = 70]$
$\frac {1 } {3}$ $= 1 : 3$
$\because$ $2 : 3$ $\neq$ $1 : 3$
$\therefore$ $32, 48, 70, 210$ are not in proportion.
$=\frac{2}{3}$ $= 2 : 3$
$70 : 210$ $=\frac{70}{210}=\frac{70 \div 70}{210 \div 70}$[$\therefore$$H.C.F. (70, 210) = 70]$
$\frac {1 } {3}$ $= 1 : 3$
$\because$ $2 : 3$ $\neq$ $1 : 3$
$\therefore$ $32, 48, 70, 210$ are not in proportion.
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