Question
Simplity the following to its lowest term: $\frac{68}{17}$
✓
Answer
$\frac{68}{17}$ Factors of $68$ are $1, 2, 4, 17, 34$ and $68$ Factors of $17$ are $1$ and $17$
Common factor of $68$ and $17$ is $17$ $HCF$ of $68$ and $17$ is = $17$
Dividing both the numerator and denominator by $17,$
we get: $\frac{68\div17}{17\div17}=\frac{4}{1}$
Therefore, the simplest form obtained is, $\frac{68}{17}=\frac{4}{1}$
Common factor of $68$ and $17$ is $17$ $HCF$ of $68$ and $17$ is = $17$
Dividing both the numerator and denominator by $17,$
we get: $\frac{68\div17}{17\div17}=\frac{4}{1}$
Therefore, the simplest form obtained is, $\frac{68}{17}=\frac{4}{1}$
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