Question
Determine if the ratio form a proportion. Also, write the middle form and extreme term where the ratio form a proportion: $39$ litres : $65$ litres and $6$ bottles : $10$ bottles.

Answer

$39$ litre $: 65$ litre $=\frac{39}{65}=\frac{39 \div 13}{65 \div 13}$[$\therefore$$H.C.F.(39, 65) = 13]$
$=\frac{3}{5}$$= 3 : 5$
$6$ bottle $: 10$ bottle $=\frac{6}{10}=\frac{6 \div 2}{10 \div 2}$ [$\therefore$$H.C.F.(6, 10) = 2]$
$=\frac{3}{5}$ $= 3 : 5$
Since the two ratios are equal, therefore, the given ratios are in proportion.
Middle terms are $65$ litres and $6$ bottles. Extreme terms are $39$ litres and $10$ bottles.

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