Question
Determine the validity of the following arguments using the direct method of truth table:
$P \rightarrow Q$
$Q \rightarrow P$
$\therefore P \leftrightarrow Q$

Answer

Combining the two bases of this argument as a whole, the argument will be as follows:
$(P \rightarrow Q)\ \&\ (Q \rightarrow P)$
$\therefore P \leftrightarrow Q$
Truth Table:
  Support Statement The resulting statement
  $1$ $2$ $3$ $4$ $5$ $6$
$P$ $Q$ $P \rightarrow Q$ $Q \rightarrow P$ $(P \rightarrow Q)\ \&\ (Q \rightarrow P)$ $P \leftrightarrow Q$
$1$ $T$ $T$ $T$ $T$ $T^*$ $T^*$
$2$ $T$ $F$ $F$ $T$ $F$ $F$
$3$ $F$ $T$ $T$ $F$ $F$ $F$
$4$ $F$ $F$ $T$ $T$ $T^*$ $T^*$
  $1,2 (\rightarrow)$ $2, 1(\rightarrow)$ $3, 4(\&)$ $1, 2(\leftrightarrow)$
Judgment of the validity of the argument: A total of six columns are presented in the above fact sheet. In which the column. $5$ in Constitution and Column. $6$ is the representation of the resultant dissection. The flower of the truth table is out of four rows. The base statement in $1$ and $4$ is the truth $‘T’$ and all the resulting statements in the same row are also the truth $‘T’.$ Hence this argument is standard.

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