Question
Devide The Following :
$\left(3 x+2 x^2+4 x^3\right) \div(x-4)$

Answer

$\left(3 x+2 x^2+4 x^3\right) \div(x-4)$
Write the dividend in descending order of their indices.
$3 x+2 x^2+4 x^3=4 x^3+2 x^2+3 x$

Image
$\therefore \text { Quotient }=4 x^2+18 x+75$
$\text { Remainder }=300$

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