Question
Devide The Following :
$\left(4 x^4-5 x^3-7 x+1\right) \div(4 x-1)$
$\left(4 x^4-5 x^3-7 x+1\right) \div(4 x-1)$
✓
Answer
$\left(4 x^4-5 x^3-7 x+1\right) \div(4 x-1)$
Write the dividend in descending order of their indices.
$\left(4 x^4-5 x^3-7 x+1\right)=\left(4 x^4-5 x^3+0 x^2-7 x+1\right)$
$\begin{aligned} & \therefore \text { Quotient }=x^3-x^2-\frac{x}{4}-\frac{29}{16} \\ & \text { Remainder }=\frac{-13}{16}\end{aligned}$
Write the dividend in descending order of their indices.
$\left(4 x^4-5 x^3-7 x+1\right)=\left(4 x^4-5 x^3+0 x^2-7 x+1\right)$
$\begin{aligned} & \therefore \text { Quotient }=x^3-x^2-\frac{x}{4}-\frac{29}{16} \\ & \text { Remainder }=\frac{-13}{16}\end{aligned}$
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