Question
Solve:
$\frac{15(2-\text{y})-5(\text{y}+6)}{1-3\text{y}}=10$
$\frac{15(2-\text{y})-5(\text{y}+6)}{1-3\text{y}}=10$
✓
Answer
$\frac{15(2-\text{y})-5(\text{y}+6)}{1-3\text{y}}=10$
$\Rightarrow\frac{30 - 15\text{y} - 5\text{y} - 30}{1 - 3\text{y}} = 10$
$\Rightarrow \frac{-20\text{y}}{1 - 3\text{y}} = 10$
$\Rightarrow1 (-20\text{y}) = 10 (1 - 3\text{y})$ (by cross multiplication)
$\Rightarrow-20\text{y} = 10 - 30\text{y}$
$\Rightarrow-20\text{y} + 30\text{y} = 10$
$\Rightarrow10\text{y} = 10$
$\Rightarrow\text{y} = \frac{10}{10} = 1$
$\therefore\text{y} = 1$
$\Rightarrow\frac{30 - 15\text{y} - 5\text{y} - 30}{1 - 3\text{y}} = 10$
$\Rightarrow \frac{-20\text{y}}{1 - 3\text{y}} = 10$
$\Rightarrow1 (-20\text{y}) = 10 (1 - 3\text{y})$ (by cross multiplication)
$\Rightarrow-20\text{y} = 10 - 30\text{y}$
$\Rightarrow-20\text{y} + 30\text{y} = 10$
$\Rightarrow10\text{y} = 10$
$\Rightarrow\text{y} = \frac{10}{10} = 1$
$\therefore\text{y} = 1$
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