Question
Devide The Following :
$\left(p^2+7 p-5\right) \div(p+3)$
$\left(p^2+7 p-5\right) \div(p+3)$
✓
Answer
$\left(p^2+7 p-5\right) \div(p+3)$
$\therefore \text { Quotient }=p+4$
$\text { Remainder }=-17$
$\therefore \text { Quotient }=p+4$
$\text { Remainder }=-17$
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→Expand :$(a+2)(a-1)$
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$\ \ \ \ \ \ \ \ \ \ \ 3\ \ \ \ 7\\\ \ \ \ \ \underline{+\text{A}\ \ \ \ \text{B}\ }\\\ \ \ \ \ {\ \ \ \ \ \ 9\ \ \ \ \text{A}\ }$
→$\ \ \ \ \ \ \ \ \ \ \ 3\ \ \ \ 7\\\ \ \ \ \ \underline{+\text{A}\ \ \ \ \text{B}\ }\\\ \ \ \ \ {\ \ \ \ \ \ 9\ \ \ \ \text{A}\ }$
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→Simplify following:
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