Question
Solve Cryptarithms.
$\ \ \ \ \ \ \ \ \ \ \ 3\ \ \ \ 7\\\ \ \ \ \ \underline{+\text{A}\ \ \ \ \text{B}\ }\\\ \ \ \ \ {\ \ \ \ \ \ 9\ \ \ \ \text{A}\ }$

Answer

Two possible values of A are:
  1. If $7+\text{B}\leq9,3+\text{A}=9$
$\therefore\text{A}=6$

But if A = 6, 7 + B must be larger than 9.

Hence, it is impossible.
  1. If $7+\text{B}\geq9$
$\therefore1+3+\text{A}=9$

$\Rightarrow\text{A}=5$

If A = 5 and 7 + B = 5,

B must be 8

$\therefore$ A = 5, B = 8

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