તથા \(K_A = hf - \phi_A ….. (1)\) અને \( K_B = 2hf - \phi_B = 2hf - 2\phi_A ….. (2)\)
સમીકરણ \((2)\) માંથી \((1)\) ને બાદ કરતાં,
\(\therefore \,\,{K_B}\, - \,\,{K_A}\, = \,\,2h{f}\, - \,\,2{\phi _A}\, - \,h{f}\, + \,{\varphi _A}\, = \,\,h{f}\, - \,\,{\phi _A}\,\,\)
\(\therefore \,\,{K_B}\, - \,\,{K_A}\, = \,{K_A}\,\) (સમીકરણ \({\text{(1)}}\))
\(\therefore \,\,{K_B} = \,\,2{K_A}\,\,\,\,\,\,\,\therefore \,\,\frac{{{K_A}}}{{{K_B}}}\,\, = \,\,\frac{1}{2}\)